Mesin Belajar: Bubble sheet multiple choice scanner and test grader

http://www.pyimagesearch.com/2016/10/03/bubble-sheet-multiple-choice-scanner-and-test-grader-using-omr-python-and-opencv/

Over the past few months I’ve gotten quite the number of requests landing in my inbox to build a bubble sheet/Scantron-like test reader using computer vision and image processing techniques.
And while I’ve been having a lot of fun doing this series on machine learning and deep learning, I’d be lying if I said this little mini-project wasn’t a short, welcome break. One of my favorite parts of running the PyImageSearch blog is demonstrating how to build actual solutions to problems using computer vision.
In fact, what makes this project so special is that we are going to combine the techniques from many previous blog posts, including building a document scanner, contour sorting, and perspective transforms. Using the knowledge gained from these previous posts, we’ll be able to make quick work of this bubble sheet scanner and test grader.
You see, last Friday afternoon I quickly Photoshopped an example bubble test paper, printed out a few copies, and then set to work on coding up the actual implementation.
Overall, I am quite pleased with this implementation and I think you’ll absolutely be able to use this bubble sheet grader/OMR system as a starting point for your own projects.
To learn more about utilizing computer vision, image processing, and OpenCV to automatically grade bubble test sheets, keep reading.

Looking for the source code to this post?
Jump right to the downloads section.

Bubble sheet scanner and test grader using OMR, Python, and OpenCV

In the remainder of this blog post, I’ll discuss what exactly Optical Mark Recognition (OMR) is. I’ll then demonstrate how to implement a bubble sheet test scanner and grader using strictly computer vision and image processing techniques, along with the OpenCV library.
Once we have our OMR system implemented, I’ll provide sample results of our test grader on a few example exams, including ones that were filled out with nefarious intent.
Finally, I’ll discuss some of the shortcomings of this current bubble sheet scanner system and how we can improve it in future iterations.

What is Optical Mark Recognition (OMR)?

Optical Mark Recognition, or OMR for short, is the process of automatically analyzing human-marked documents and interpreting their results.
Arguably, the most famous, easily recognizable form of OMR are bubble sheet multiple choice tests, not unlike the ones you took in elementary school, middle school, or even high school.
If you’re unfamiliar with “bubble sheet tests” or the trademark/corporate name of “Scantron tests”, they are simply multiple-choice tests that you take as a student. Each question on the exam is a multiple choice — and you use a #2 pencil to mark the “bubble” that corresponds to the correct answer.
The most notable bubble sheet test you experienced (at least in the United States) were taking the SATs during high school, prior to filling out college admission applications.
I believe that the SATs use the software provided by Scantron to perform OMR and grade student exams, but I could easily be wrong there. I only make note of this because Scantron is used in over 98% of all US school districts.
In short, what I’m trying to say is that there is a massive market for Optical Mark Recognition and the ability to grade and interpret human-marked forms and exams.

Implementing a bubble sheet scanner and grader using OMR, Python, and OpenCV

Now that we understand the basics of OMR, let’s build a computer vision system using Python and OpenCV that can read and grade bubble sheet tests.
Of course, I’ll be providing lots of visual example images along the way so you can understand exactly what techniques I’m applying and why I’m using them.
Below I have included an example filled in bubble sheet exam that I have put together for this project:

Figure 1: The example, filled in bubble sheet we are going to use when developing our test scanner software.

We’ll be using this as our example image as we work through the steps of building our test grader. Later in this lesson, you’ll also find additional sample exams.
I have also included a blank exam template as a .PSD (Photoshop) file so you can modify it as you see fit. You can use the “Downloads” section at the bottom of this post to download the code, example images, and template file.

The 7 steps to build a bubble sheet scanner and grader

The goal of this blog post is to build a bubble sheet scanner and test grader using Python and OpenCV.
To accomplish this, our implementation will need to satisfy the following 7 steps:

Step #1: Detect the exam in an image.
Step #2: Apply a perspective transform to extract the top-down, birds-eye-view of the exam.
Step #3: Extract the set of bubbles (i.e., the possible answer choices) from the perspective transformed exam.
Step #4: Sort the questions/bubbles into rows.
Step #5: Determine the marked (i.e., “bubbled in”) answer for each row.
Step #6: Lookup the correct answer in our answer key to determine if the user was correct in their choice.
Step #7: Repeat for all questions in the exam.

The next section of this tutorial will cover the actual implementation of our algorithm.

The bubble sheet scanner implementation with Python and OpenCV

To get started, open up a new file, name it test_grader.py , and let’s get to work:

# import the necessary packages
from imutils.perspective import four_point_transform
from imutils import contours
import numpy as np
import argparse
import imutils
import cv2

# construct the argument parse and parse the arguments
ap = argparse.ArgumentParser()
ap.add_argument("-i", "--image", required=True,
 help="path to the input image")
args = vars(ap.parse_args())

# define the answer key which maps the question number
# to the correct answer
ANSWER_KEY = {0: 1, 1: 4, 2: 0, 3: 3, 4: 1}

# import the necessary packages

from imutils.perspective import four_point_transform

from imutils import contours

import numpy as np

import argparse

import imutils

import cv2

# construct the argument parse and parse the arguments

ap = argparse.ArgumentParser()

ap.add_argument("-i", "--image", required=True,

help="path to the input image")

args = vars(ap.parse_args())

# define the answer key which maps the question number

# to the correct answer

ANSWER_KEY = {0: 1, 1: 4, 2: 0, 3: 3, 4: 1}

On Lines 2-7 we import our required Python packages.
You should already have OpenCV and Numpy installed on your system, but you might not have the most recent version of imutils, my set of convenience functions to make performing basic image processing operations easier. To install imutils (or upgrade to the latest version), just execute the following command:

$ pip install --upgrade imutils

1	$ pip install --upgrade imutils

Lines 10-12 parse our command line arguments. We only need a single switch here, --image , which is the path to the input bubble sheet test image that we are going to grade for correctness.
Line 17 then defines our ANSWER_KEY .
As the name of the variable suggests, the ANSWER_KEY provides integer mappings of the question numbers to the index of the correct bubble.
In this case, a key of 0 indicates the first question, while a value of 1 signifies “B” as the correct answer (since “B” is the index 1 in the string “ABCDE”). As a second example, consider a key of 1 that maps to a value of 4 — this would indicate that the answer to the second question is “E”.
As a matter of convenience, I have written the entire answer key in plain english here:

Question #1: B
Question #2: E
Question #3: A
Question #4: D
Question #5: B

Next, let’s preprocess our input image:

# import the necessary packages
from imutils.perspective import four_point_transform
from imutils import contours
import numpy as np
import argparse
import imutils
import cv2

# construct the argument parse and parse the arguments
ap = argparse.ArgumentParser()
ap.add_argument("-i", "--image", required=True,
 help="path to the input image")
args = vars(ap.parse_args())

# define the answer key which maps the question number
# to the correct answer
ANSWER_KEY = {0: 1, 1: 4, 2: 0, 3: 3, 4: 1}

# load the image, convert it to grayscale, blur it
# slightly, then find edges
image = cv2.imread(args["image"])
gray = cv2.cvtColor(image, cv2.COLOR_BGR2GRAY)
blurred = cv2.GaussianBlur(gray, (5, 5), 0)
edged = cv2.Canny(blurred, 75, 200)

# load the image, convert it to grayscale, blur it

# slightly, then find edges

image = cv2.imread(args["image"])

gray = cv2.cvtColor(image, cv2.COLOR_BGR2GRAY)

blurred = cv2.GaussianBlur(gray, (5, 5), 0)

edged = cv2.Canny(blurred, 75, 200)

On Line 21 we load our image from disk, followed by converting it to grayscale (Line 22), and blurring it to reduce high frequency noise (Line 23).
We then apply the Canny edge detector on Line 24 to find the edges/outlines of the exam.
Below I have included a screenshot of our exam after applying edge detection:

Figure 2: Applying edge detection to our exam neatly reveals the outlines of the paper.

Notice how the edges of the document are clearly defined, with all four vertices of the exam being present in the image.
Obtaining this silhouette of the document is extremely important in our next step as we will use it as a marker to apply a perspective transform to the exam, obtaining a top-down, birds-eye-view of the document:

# import the necessary packages
from imutils.perspective import four_point_transform
from imutils import contours
import numpy as np
import argparse
import imutils
import cv2

# construct the argument parse and parse the arguments
ap = argparse.ArgumentParser()
ap.add_argument("-i", "--image", required=True,
 help="path to the input image")
args = vars(ap.parse_args())

# define the answer key which maps the question number
# to the correct answer
ANSWER_KEY = {0: 1, 1: 4, 2: 0, 3: 3, 4: 1}

# load the image, convert it to grayscale, blur it
# slightly, then find edges
image = cv2.imread(args["image"])
gray = cv2.cvtColor(image, cv2.COLOR_BGR2GRAY)
blurred = cv2.GaussianBlur(gray, (5, 5), 0)
edged = cv2.Canny(blurred, 75, 200)

# find contours in the edge map, then initialize
# the contour that corresponds to the document
cnts = cv2.findContours(edged.copy(), cv2.RETR_EXTERNAL,
 cv2.CHAIN_APPROX_SIMPLE)
cnts = cnts[0] if imutils.is_cv2() else cnts[1]
docCnt = None

# ensure that at least one contour was found
if len(cnts) > 0:
 # sort the contours according to their size in
 # descending order
 cnts = sorted(cnts, key=cv2.contourArea, reverse=True)

 # loop over the sorted contours
 for c in cnts:
  # approximate the contour
  peri = cv2.arcLength(c, True)
  approx = cv2.approxPolyDP(c, 0.02 * peri, True)

  # if our approximated contour has four points,
  # then we can assume we have found the paper
  if len(approx) == 4:
   docCnt = approx
   break

# find contours in the edge map, then initialize

# the contour that corresponds to the document

cnts = cv2.findContours(edged.copy(), cv2.RETR_EXTERNAL,

cv2.CHAIN_APPROX_SIMPLE)

cnts = cnts[0] if imutils.is_cv2() else cnts[1]

docCnt = None

# ensure that at least one contour was found

if len(cnts) > 0:

# sort the contours according to their size in

# descending order

cnts = sorted(cnts, key=cv2.contourArea, reverse=True)

# loop over the sorted contours

for c in cnts:

# approximate the contour

peri = cv2.arcLength(c, True)

approx = cv2.approxPolyDP(c, 0.02 * peri, True)

# if our approximated contour has four points,

# then we can assume we have found the paper

if len(approx) == 4:

docCnt = approx

break

Now that we have the outline of our exam, we apply the cv2.findContours function to find the lines that correspond to the exam itself.
We do this by sorting our contours by their area (from largest to smallest) on Line 37 (after making sure at least one contour was found on Line 34, of course). This implies that larger contours will be placed at the front of the list, while smaller contours will appear farther back in the list.
We make the assumption that our exam will be the main focal point of the image, and thus be larger than other objects in the image. This assumption allows us to “filter” our contours, simply by investigating their area and knowing that the contour that corresponds to the exam should be near the front of the list.
However, contour area and size is not enough — we should also check the number of vertices on the contour.
To do, this, we loop over each of our (sorted) contours on Line 40. For each of them, we approximate the contour, which in essence means we simplify the number of points in the contour, making it a “more basic” geometric shape. You can read more about contour approximation in this post on building a mobile document scanner.
On Line 47 we make a check to see if our approximated contour has four points, and if it does, we assume that we have found the exam.
Below I have included an example image that demonstrates the docCnt variable being drawn on the original image:

Figure 3: An example of drawing the contour associated with the exam on our original image, indicating that we have successfully found the exam.

Sure enough, this area corresponds to the outline of the exam.
Now that we have used contours to find the outline of the exam, we can apply a perspective transform to obtain a top-down, birds-eye-view of the document:

# import the necessary packages
from imutils.perspective import four_point_transform
from imutils import contours
import numpy as np
import argparse
import imutils
import cv2

# construct the argument parse and parse the arguments
ap = argparse.ArgumentParser()
ap.add_argument("-i", "--image", required=True,
 help="path to the input image")
args = vars(ap.parse_args())

# define the answer key which maps the question number
# to the correct answer
ANSWER_KEY = {0: 1, 1: 4, 2: 0, 3: 3, 4: 1}

# load the image, convert it to grayscale, blur it
# slightly, then find edges
image = cv2.imread(args["image"])
gray = cv2.cvtColor(image, cv2.COLOR_BGR2GRAY)
blurred = cv2.GaussianBlur(gray, (5, 5), 0)
edged = cv2.Canny(blurred, 75, 200)

# find contours in the edge map, then initialize
# the contour that corresponds to the document
cnts = cv2.findContours(edged.copy(), cv2.RETR_EXTERNAL,
 cv2.CHAIN_APPROX_SIMPLE)
cnts = cnts[0] if imutils.is_cv2() else cnts[1]
docCnt = None

# ensure that at least one contour was found
if len(cnts) > 0:
 # sort the contours according to their size in
 # descending order
 cnts = sorted(cnts, key=cv2.contourArea, reverse=True)

 # loop over the sorted contours
 for c in cnts:
  # approximate the contour
  peri = cv2.arcLength(c, True)
  approx = cv2.approxPolyDP(c, 0.02 * peri, True)

  # if our approximated contour has four points,
  # then we can assume we have found the paper
  if len(approx) == 4:
   docCnt = approx
   break

# apply a four point perspective transform to both the
# original image and grayscale image to obtain a top-down
# birds eye view of the paper
paper = four_point_transform(image, docCnt.reshape(4, 2))
warped = four_point_transform(gray, docCnt.reshape(4, 2))

# apply a four point perspective transform to both the

# original image and grayscale image to obtain a top-down

# birds eye view of the paper

paper = four_point_transform(image, docCnt.reshape(4, 2))

warped = four_point_transform(gray, docCnt.reshape(4, 2))

In this case, we’ll be using my implementation of the four_point_transform function which:

Orders the (x, y)-coordinates of our contours in a specific, reproducible manner.
Applies a perspective transform to the region.

You can learn more about the perspective transform in this post as well as this updated one on coordinate ordering, but for the time being, simply understand that this function handles taking the “skewed” exam and transforms it, returning a top-down view of the document:

Figure 4: Obtaining a top-down, birds-eye view of both the original image along with the grayscale version.

Figure 4: Obtaining a top-down, birds-eye view of both the original image (left) along with the grayscale version (right).

Alright, so now we’re getting somewhere.
We found our exam in the original image.
We applied a perspective transform to obtain a 90 degree viewing angle of the document.
But how do we go about actually grading the document?
This step starts with binarization, or the process of thresholding/segmenting the foreground from the background of the image:

# import the necessary packages
from imutils.perspective import four_point_transform
from imutils import contours
import numpy as np
import argparse
import imutils
import cv2

# construct the argument parse and parse the arguments
ap = argparse.ArgumentParser()
ap.add_argument("-i", "--image", required=True,
 help="path to the input image")
args = vars(ap.parse_args())

# define the answer key which maps the question number
# to the correct answer
ANSWER_KEY = {0: 1, 1: 4, 2: 0, 3: 3, 4: 1}

# load the image, convert it to grayscale, blur it
# slightly, then find edges
image = cv2.imread(args["image"])
gray = cv2.cvtColor(image, cv2.COLOR_BGR2GRAY)
blurred = cv2.GaussianBlur(gray, (5, 5), 0)
edged = cv2.Canny(blurred, 75, 200)

# find contours in the edge map, then initialize
# the contour that corresponds to the document
cnts = cv2.findContours(edged.copy(), cv2.RETR_EXTERNAL,
 cv2.CHAIN_APPROX_SIMPLE)
cnts = cnts[0] if imutils.is_cv2() else cnts[1]
docCnt = None

# ensure that at least one contour was found
if len(cnts) > 0:
 # sort the contours according to their size in
 # descending order
 cnts = sorted(cnts, key=cv2.contourArea, reverse=True)

 # loop over the sorted contours
 for c in cnts:
  # approximate the contour
  peri = cv2.arcLength(c, True)
  approx = cv2.approxPolyDP(c, 0.02 * peri, True)

  # if our approximated contour has four points,
  # then we can assume we have found the paper
  if len(approx) == 4:
   docCnt = approx
   break

# apply a four point perspective transform to both the
# original image and grayscale image to obtain a top-down
# birds eye view of the paper
paper = four_point_transform(image, docCnt.reshape(4, 2))
warped = four_point_transform(gray, docCnt.reshape(4, 2))

# apply Otsu's thresholding method to binarize the warped
# piece of paper
thresh = cv2.threshold(warped, 0, 255,
 cv2.THRESH_BINARY_INV | cv2.THRESH_OTSU)[1]

# apply Otsu's thresholding method to binarize the warped

# piece of paper

thresh = cv2.threshold(warped, 0, 255,

cv2.THRESH_BINARY_INV | cv2.THRESH_OTSU)[1]

After applying Otsu’s thresholding method, our exam is now a binary image:

Figure 5: Using Otsu’s thresholding allows us to segment the foreground from the background of the image.

Notice how the background of the image is black, while the foreground is white.
This binarization will allow us to once again apply contour extraction techniques to find each of the bubbles in the exam:

# import the necessary packages
from imutils.perspective import four_point_transform
from imutils import contours
import numpy as np
import argparse
import imutils
import cv2

# construct the argument parse and parse the arguments
ap = argparse.ArgumentParser()
ap.add_argument("-i", "--image", required=True,
 help="path to the input image")
args = vars(ap.parse_args())

# define the answer key which maps the question number
# to the correct answer
ANSWER_KEY = {0: 1, 1: 4, 2: 0, 3: 3, 4: 1}

# load the image, convert it to grayscale, blur it
# slightly, then find edges
image = cv2.imread(args["image"])
gray = cv2.cvtColor(image, cv2.COLOR_BGR2GRAY)
blurred = cv2.GaussianBlur(gray, (5, 5), 0)
edged = cv2.Canny(blurred, 75, 200)

# find contours in the edge map, then initialize
# the contour that corresponds to the document
cnts = cv2.findContours(edged.copy(), cv2.RETR_EXTERNAL,
 cv2.CHAIN_APPROX_SIMPLE)
cnts = cnts[0] if imutils.is_cv2() else cnts[1]
docCnt = None

# ensure that at least one contour was found
if len(cnts) > 0:
 # sort the contours according to their size in
 # descending order
 cnts = sorted(cnts, key=cv2.contourArea, reverse=True)

 # loop over the sorted contours
 for c in cnts:
  # approximate the contour
  peri = cv2.arcLength(c, True)
  approx = cv2.approxPolyDP(c, 0.02 * peri, True)

  # if our approximated contour has four points,
  # then we can assume we have found the paper
  if len(approx) == 4:
   docCnt = approx
   break

# apply a four point perspective transform to both the
# original image and grayscale image to obtain a top-down
# birds eye view of the paper
paper = four_point_transform(image, docCnt.reshape(4, 2))
warped = four_point_transform(gray, docCnt.reshape(4, 2))

# apply Otsu's thresholding method to binarize the warped
# piece of paper
thresh = cv2.threshold(warped, 0, 255,
 cv2.THRESH_BINARY_INV | cv2.THRESH_OTSU)[1]

# find contours in the thresholded image, then initialize
# the list of contours that correspond to questions
cnts = cv2.findContours(thresh.copy(), cv2.RETR_EXTERNAL,
 cv2.CHAIN_APPROX_SIMPLE)
cnts = cnts[0] if imutils.is_cv2() else cnts[1]
questionCnts = []

# loop over the contours
for c in cnts:
 # compute the bounding box of the contour, then use the
 # bounding box to derive the aspect ratio
 (x, y, w, h) = cv2.boundingRect(c)
 ar = w / float(h)

 # in order to label the contour as a question, region
 # should be sufficiently wide, sufficiently tall, and
 # have an aspect ratio approximately equal to 1
 if w >= 20 and h >= 20 and ar >= 0.9 and ar <= 1.1:
  questionCnts.append(c)

# find contours in the thresholded image, then initialize

# the list of contours that correspond to questions

cnts = cv2.findContours(thresh.copy(), cv2.RETR_EXTERNAL,

cv2.CHAIN_APPROX_SIMPLE)

cnts = cnts[0] if imutils.is_cv2() else cnts[1]

questionCnts = []

# loop over the contours

for c in cnts:

# compute the bounding box of the contour, then use the

# bounding box to derive the aspect ratio

(x, y, w, h) = cv2.boundingRect(c)

ar = w / float(h)

# in order to label the contour as a question, region

# should be sufficiently wide, sufficiently tall, and

# have an aspect ratio approximately equal to 1

if w >= 20 and h >= 20 and ar >= 0.9 and ar <= 1.1:

questionCnts.append(c)

Lines 64-67 handle finding contours on our thresh binary image, followed by initializing questionCnts , a list of contours that correspond to the questions/bubbles on the exam.
To determine which regions of the image are bubbles, we first loop over each of the individual contours (Line 70).
For each of these contours, we compute the bounding box (Line 73), which also allows us to compute the aspect ratio, or more simply, the ratio of the width to the height (Line 74).
In order for a contour area to be considered a bubble, the region should:

Be sufficiently wide and tall (in this case, at least 20 pixels in both dimensions).
Have an aspect ratio that is approximately equal to 1.

As long as these checks hold, we can update our questionCnts list and mark the region as a bubble.
Below I have included a screenshot that has drawn the output of questionCnts on our image:

Figure 6: Using contour filtering allows us to find all the question bubbles in our bubble sheet exam recognition software.

Notice how only the question regions of the exam are highlighted and nothing else.
We can now move on to the “grading” portion of our OMR system:

# import the necessary packages
from imutils.perspective import four_point_transform
from imutils import contours
import numpy as np
import argparse
import imutils
import cv2

# construct the argument parse and parse the arguments
ap = argparse.ArgumentParser()
ap.add_argument("-i", "--image", required=True,
 help="path to the input image")
args = vars(ap.parse_args())

# define the answer key which maps the question number
# to the correct answer
ANSWER_KEY = {0: 1, 1: 4, 2: 0, 3: 3, 4: 1}

# load the image, convert it to grayscale, blur it
# slightly, then find edges
image = cv2.imread(args["image"])
gray = cv2.cvtColor(image, cv2.COLOR_BGR2GRAY)
blurred = cv2.GaussianBlur(gray, (5, 5), 0)
edged = cv2.Canny(blurred, 75, 200)

# find contours in the edge map, then initialize
# the contour that corresponds to the document
cnts = cv2.findContours(edged.copy(), cv2.RETR_EXTERNAL,
 cv2.CHAIN_APPROX_SIMPLE)
cnts = cnts[0] if imutils.is_cv2() else cnts[1]
docCnt = None

# ensure that at least one contour was found
if len(cnts) > 0:
 # sort the contours according to their size in
 # descending order
 cnts = sorted(cnts, key=cv2.contourArea, reverse=True)

 # loop over the sorted contours
 for c in cnts:
  # approximate the contour
  peri = cv2.arcLength(c, True)
  approx = cv2.approxPolyDP(c, 0.02 * peri, True)

  # if our approximated contour has four points,
  # then we can assume we have found the paper
  if len(approx) == 4:
   docCnt = approx
   break

# apply a four point perspective transform to both the
# original image and grayscale image to obtain a top-down
# birds eye view of the paper
paper = four_point_transform(image, docCnt.reshape(4, 2))
warped = four_point_transform(gray, docCnt.reshape(4, 2))

# apply Otsu's thresholding method to binarize the warped
# piece of paper
thresh = cv2.threshold(warped, 0, 255,
 cv2.THRESH_BINARY_INV | cv2.THRESH_OTSU)[1]

# find contours in the thresholded image, then initialize
# the list of contours that correspond to questions
cnts = cv2.findContours(thresh.copy(), cv2.RETR_EXTERNAL,
 cv2.CHAIN_APPROX_SIMPLE)
cnts = cnts[0] if imutils.is_cv2() else cnts[1]
questionCnts = []

# loop over the contours
for c in cnts:
 # compute the bounding box of the contour, then use the
 # bounding box to derive the aspect ratio
 (x, y, w, h) = cv2.boundingRect(c)
 ar = w / float(h)

 # in order to label the contour as a question, region
 # should be sufficiently wide, sufficiently tall, and
 # have an aspect ratio approximately equal to 1
 if w >= 20 and h >= 20 and ar >= 0.9 and ar <= 1.1:
  questionCnts.append(c)

# sort the question contours top-to-bottom, then initialize
# the total number of correct answers
questionCnts = contours.sort_contours(questionCnts,
 method="top-to-bottom")[0]
correct = 0

# each question has 5 possible answers, to loop over the
# question in batches of 5
for (q, i) in enumerate(np.arange(0, len(questionCnts), 5)):
 # sort the contours for the current question from
 # left to right, then initialize the index of the
 # bubbled answer
 cnts = contours.sort_contours(questionCnts[i:i + 5])[0]
 bubbled = None

# sort the question contours top-to-bottom, then initialize

# the total number of correct answers

questionCnts = contours.sort_contours(questionCnts,

method="top-to-bottom")[0]

correct = 0

# each question has 5 possible answers, to loop over the

# question in batches of 5

for (q, i) in enumerate(np.arange(0, len(questionCnts), 5)):

# sort the contours for the current question from

# left to right, then initialize the index of the

# bubbled answer

cnts = contours.sort_contours(questionCnts[i:i + 5])[0]

bubbled = None

First, we must sort our questionCnts from top-to-bottom. This will ensure that rows of questions that are closer to the top of the exam will appear first in the sorted list.
We also initialize a bookkeeper variable to keep track of the number of correct answers.
On Line 90 we start looping over our questions. Since each question has 5 possible answers, we’ll apply NumPy array slicing and contour sorting to to sort the current set of contours from left to right.
The reason this methodology works is because we have already sorted our contours from top-to-bottom. We know that the 5 bubbles for each question will appear sequentially in our list — but we do not know whether these bubbles will be sorted from left-to-right. The sort contour call on Line 94 takes care of this issue and ensures each row of contours are sorted into rows, from left-to-right.
To visualize this concept, I have included a screenshot below that depicts each row of questions as a separate color:

Figure 7: By sorting our contours from top-to-bottom, followed by left-to-right, we can extract each row of bubbles. Therefore, each row is equal to the bubbles for one question.

Given a row of bubbles, the next step is to determine which bubble is filled in.
We can accomplish this by using our thresh image and counting the number of non-zero pixels (i.e., foreground pixels) in each bubble region:

# import the necessary packages
from imutils.perspective import four_point_transform
from imutils import contours
import numpy as np
import argparse
import imutils
import cv2

# construct the argument parse and parse the arguments
ap = argparse.ArgumentParser()
ap.add_argument("-i", "--image", required=True,
 help="path to the input image")
args = vars(ap.parse_args())

# define the answer key which maps the question number
# to the correct answer
ANSWER_KEY = {0: 1, 1: 4, 2: 0, 3: 3, 4: 1}

# load the image, convert it to grayscale, blur it
# slightly, then find edges
image = cv2.imread(args["image"])
gray = cv2.cvtColor(image, cv2.COLOR_BGR2GRAY)
blurred = cv2.GaussianBlur(gray, (5, 5), 0)
edged = cv2.Canny(blurred, 75, 200)

# find contours in the edge map, then initialize
# the contour that corresponds to the document
cnts = cv2.findContours(edged.copy(), cv2.RETR_EXTERNAL,
 cv2.CHAIN_APPROX_SIMPLE)
cnts = cnts[0] if imutils.is_cv2() else cnts[1]
docCnt = None

# ensure that at least one contour was found
if len(cnts) > 0:
 # sort the contours according to their size in
 # descending order
 cnts = sorted(cnts, key=cv2.contourArea, reverse=True)

 # loop over the sorted contours
 for c in cnts:
  # approximate the contour
  peri = cv2.arcLength(c, True)
  approx = cv2.approxPolyDP(c, 0.02 * peri, True)

  # if our approximated contour has four points,
  # then we can assume we have found the paper
  if len(approx) == 4:
   docCnt = approx
   break

# apply a four point perspective transform to both the
# original image and grayscale image to obtain a top-down
# birds eye view of the paper
paper = four_point_transform(image, docCnt.reshape(4, 2))
warped = four_point_transform(gray, docCnt.reshape(4, 2))

# apply Otsu's thresholding method to binarize the warped
# piece of paper
thresh = cv2.threshold(warped, 0, 255,
 cv2.THRESH_BINARY_INV | cv2.THRESH_OTSU)[1]

# find contours in the thresholded image, then initialize
# the list of contours that correspond to questions
cnts = cv2.findContours(thresh.copy(), cv2.RETR_EXTERNAL,
 cv2.CHAIN_APPROX_SIMPLE)
cnts = cnts[0] if imutils.is_cv2() else cnts[1]
questionCnts = []

# loop over the contours
for c in cnts:
 # compute the bounding box of the contour, then use the
 # bounding box to derive the aspect ratio
 (x, y, w, h) = cv2.boundingRect(c)
 ar = w / float(h)

 # in order to label the contour as a question, region
 # should be sufficiently wide, sufficiently tall, and
 # have an aspect ratio approximately equal to 1
 if w >= 20 and h >= 20 and ar >= 0.9 and ar <= 1.1:
  questionCnts.append(c)

# sort the question contours top-to-bottom, then initialize
# the total number of correct answers
questionCnts = contours.sort_contours(questionCnts,
 method="top-to-bottom")[0]
correct = 0

# each question has 5 possible answers, to loop over the
# question in batches of 5
for (q, i) in enumerate(np.arange(0, len(questionCnts), 5)):
 # sort the contours for the current question from
 # left to right, then initialize the index of the
 # bubbled answer
 cnts = contours.sort_contours(questionCnts[i:i + 5])[0]
 bubbled = None

 # loop over the sorted contours
 for (j, c) in enumerate(cnts):
  # construct a mask that reveals only the current
  # "bubble" for the question
  mask = np.zeros(thresh.shape, dtype="uint8")
  cv2.drawContours(mask, [c], -1, 255, -1)

  # apply the mask to the thresholded image, then
  # count the number of non-zero pixels in the
  # bubble area
  mask = cv2.bitwise_and(thresh, thresh, mask=mask)
  total = cv2.countNonZero(mask)

  # if the current total has a larger number of total
  # non-zero pixels, then we are examining the currently
  # bubbled-in answer
  if bubbled is None or total > bubbled[0]:
   bubbled = (total, j)

100

101

102

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107

108

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113

114

# loop over the sorted contours

for (j, c) in enumerate(cnts):

# construct a mask that reveals only the current

# "bubble" for the question

mask = np.zeros(thresh.shape, dtype="uint8")

cv2.drawContours(mask, [c], -1, 255, -1)

# apply the mask to the thresholded image, then

# count the number of non-zero pixels in the

# bubble area

mask = cv2.bitwise_and(thresh, thresh, mask=mask)

total = cv2.countNonZero(mask)

# if the current total has a larger number of total

# non-zero pixels, then we are examining the currently

# bubbled-in answer

if bubbled is None or total > bubbled[0]:

bubbled = (total, j)

Line 98 handles looping over each of the sorted bubbles in the row.
We then construct a mask for the current bubble on Line 101 and then count the number of non-zero pixels in the masked region (Lines 107 and 108). The more non-zero pixels we count, then the more foreground pixels there are, and therefore the bubble with the maximum non-zero count is the index of the bubble that the the test taker has bubbled in (Line 113 and 114).
Below I have included an example of creating and applying a mask to each bubble associated with a question:

Figure 8: An example of constructing a mask for each bubble in a row.

Clearly, the bubble associated with “B” has the most thresholded pixels, and is therefore the bubble that the user has marked on their exam.
This next code block handles looking up the correct answer in the ANSWER_KEY , updating any relevant bookkeeper variables, and finally drawing the marked bubble on our image:

# import the necessary packages
from imutils.perspective import four_point_transform
from imutils import contours
import numpy as np
import argparse
import imutils
import cv2

# construct the argument parse and parse the arguments
ap = argparse.ArgumentParser()
ap.add_argument("-i", "--image", required=True,
 help="path to the input image")
args = vars(ap.parse_args())

# define the answer key which maps the question number
# to the correct answer
ANSWER_KEY = {0: 1, 1: 4, 2: 0, 3: 3, 4: 1}

# load the image, convert it to grayscale, blur it
# slightly, then find edges
image = cv2.imread(args["image"])
gray = cv2.cvtColor(image, cv2.COLOR_BGR2GRAY)
blurred = cv2.GaussianBlur(gray, (5, 5), 0)
edged = cv2.Canny(blurred, 75, 200)

# find contours in the edge map, then initialize
# the contour that corresponds to the document
cnts = cv2.findContours(edged.copy(), cv2.RETR_EXTERNAL,
 cv2.CHAIN_APPROX_SIMPLE)
cnts = cnts[0] if imutils.is_cv2() else cnts[1]
docCnt = None

# ensure that at least one contour was found
if len(cnts) > 0:
 # sort the contours according to their size in
 # descending order
 cnts = sorted(cnts, key=cv2.contourArea, reverse=True)

 # loop over the sorted contours
 for c in cnts:
  # approximate the contour
  peri = cv2.arcLength(c, True)
  approx = cv2.approxPolyDP(c, 0.02 * peri, True)

  # if our approximated contour has four points,
  # then we can assume we have found the paper
  if len(approx) == 4:
   docCnt = approx
   break

# apply a four point perspective transform to both the
# original image and grayscale image to obtain a top-down
# birds eye view of the paper
paper = four_point_transform(image, docCnt.reshape(4, 2))
warped = four_point_transform(gray, docCnt.reshape(4, 2))

# apply Otsu's thresholding method to binarize the warped
# piece of paper
thresh = cv2.threshold(warped, 0, 255,
 cv2.THRESH_BINARY_INV | cv2.THRESH_OTSU)[1]

# find contours in the thresholded image, then initialize
# the list of contours that correspond to questions
cnts = cv2.findContours(thresh.copy(), cv2.RETR_EXTERNAL,
 cv2.CHAIN_APPROX_SIMPLE)
cnts = cnts[0] if imutils.is_cv2() else cnts[1]
questionCnts = []

# loop over the contours
for c in cnts:
 # compute the bounding box of the contour, then use the
 # bounding box to derive the aspect ratio
 (x, y, w, h) = cv2.boundingRect(c)
 ar = w / float(h)

 # in order to label the contour as a question, region
 # should be sufficiently wide, sufficiently tall, and
 # have an aspect ratio approximately equal to 1
 if w >= 20 and h >= 20 and ar >= 0.9 and ar <= 1.1:
  questionCnts.append(c)

# sort the question contours top-to-bottom, then initialize
# the total number of correct answers
questionCnts = contours.sort_contours(questionCnts,
 method="top-to-bottom")[0]
correct = 0

# each question has 5 possible answers, to loop over the
# question in batches of 5
for (q, i) in enumerate(np.arange(0, len(questionCnts), 5)):
 # sort the contours for the current question from
 # left to right, then initialize the index of the
 # bubbled answer
 cnts = contours.sort_contours(questionCnts[i:i + 5])[0]
 bubbled = None

 # loop over the sorted contours
 for (j, c) in enumerate(cnts):
  # construct a mask that reveals only the current
  # "bubble" for the question
  mask = np.zeros(thresh.shape, dtype="uint8")
  cv2.drawContours(mask, [c], -1, 255, -1)

  # apply the mask to the thresholded image, then
  # count the number of non-zero pixels in the
  # bubble area
  mask = cv2.bitwise_and(thresh, thresh, mask=mask)
  total = cv2.countNonZero(mask)

  # if the current total has a larger number of total
  # non-zero pixels, then we are examining the currently
  # bubbled-in answer
  if bubbled is None or total > bubbled[0]:
   bubbled = (total, j)

 # initialize the contour color and the index of the
 # *correct* answer
 color = (0, 0, 255)
 k = ANSWER_KEY[q]

 # check to see if the bubbled answer is correct
 if k == bubbled[1]:
  color = (0, 255, 0)
  correct += 1

 # draw the outline of the correct answer on the test
 cv2.drawContours(paper, [cnts[k]], -1, color, 3)

116

117

118

119

120

121

122

123

124

125

126

127

# initialize the contour color and the index of the

# *correct* answer

color = (0, 0, 255)

k = ANSWER_KEY[q]

# check to see if the bubbled answer is correct

if k == bubbled[1]:

color = (0, 255, 0)

correct += 1

# draw the outline of the correct answer on the test

cv2.drawContours(paper, [cnts[k]], -1, color, 3)

Based on whether the test taker was correct or incorrect yields which color is drawn on the exam. If the test taker is correct, we’ll highlight their answer in green. However, if the test taker made a mistake and marked an incorrect answer, we’ll let them know by highlighting the correct answer in red:

Figure 9: Drawing a “green” circle to mark “correct” or a “red” circle to mark “incorrect”.

Finally, our last code block handles scoring the exam and displaying the results to our screen:

# import the necessary packages
from imutils.perspective import four_point_transform
from imutils import contours
import numpy as np
import argparse
import imutils
import cv2

# construct the argument parse and parse the arguments
ap = argparse.ArgumentParser()
ap.add_argument("-i", "--image", required=True,
 help="path to the input image")
args = vars(ap.parse_args())

# define the answer key which maps the question number
# to the correct answer
ANSWER_KEY = {0: 1, 1: 4, 2: 0, 3: 3, 4: 1}

# load the image, convert it to grayscale, blur it
# slightly, then find edges
image = cv2.imread(args["image"])
gray = cv2.cvtColor(image, cv2.COLOR_BGR2GRAY)
blurred = cv2.GaussianBlur(gray, (5, 5), 0)
edged = cv2.Canny(blurred, 75, 200)

# find contours in the edge map, then initialize
# the contour that corresponds to the document
cnts = cv2.findContours(edged.copy(), cv2.RETR_EXTERNAL,
 cv2.CHAIN_APPROX_SIMPLE)
cnts = cnts[0] if imutils.is_cv2() else cnts[1]
docCnt = None

# ensure that at least one contour was found
if len(cnts) > 0:
 # sort the contours according to their size in
 # descending order
 cnts = sorted(cnts, key=cv2.contourArea, reverse=True)

 # loop over the sorted contours
 for c in cnts:
  # approximate the contour
  peri = cv2.arcLength(c, True)
  approx = cv2.approxPolyDP(c, 0.02 * peri, True)

  # if our approximated contour has four points,
  # then we can assume we have found the paper
  if len(approx) == 4:
   docCnt = approx
   break

# apply a four point perspective transform to both the
# original image and grayscale image to obtain a top-down
# birds eye view of the paper
paper = four_point_transform(image, docCnt.reshape(4, 2))
warped = four_point_transform(gray, docCnt.reshape(4, 2))

# apply Otsu's thresholding method to binarize the warped
# piece of paper
thresh = cv2.threshold(warped, 0, 255,
 cv2.THRESH_BINARY_INV | cv2.THRESH_OTSU)[1]

# find contours in the thresholded image, then initialize
# the list of contours that correspond to questions
cnts = cv2.findContours(thresh.copy(), cv2.RETR_EXTERNAL,
 cv2.CHAIN_APPROX_SIMPLE)
cnts = cnts[0] if imutils.is_cv2() else cnts[1]
questionCnts = []

# loop over the contours
for c in cnts:
 # compute the bounding box of the contour, then use the
 # bounding box to derive the aspect ratio
 (x, y, w, h) = cv2.boundingRect(c)
 ar = w / float(h)

 # in order to label the contour as a question, region
 # should be sufficiently wide, sufficiently tall, and
 # have an aspect ratio approximately equal to 1
 if w >= 20 and h >= 20 and ar >= 0.9 and ar <= 1.1:
  questionCnts.append(c)

# sort the question contours top-to-bottom, then initialize
# the total number of correct answers
questionCnts = contours.sort_contours(questionCnts,
 method="top-to-bottom")[0]
correct = 0

# each question has 5 possible answers, to loop over the
# question in batches of 5
for (q, i) in enumerate(np.arange(0, len(questionCnts), 5)):
 # sort the contours for the current question from
 # left to right, then initialize the index of the
 # bubbled answer
 cnts = contours.sort_contours(questionCnts[i:i + 5])[0]
 bubbled = None

 # loop over the sorted contours
 for (j, c) in enumerate(cnts):
  # construct a mask that reveals only the current
  # "bubble" for the question
  mask = np.zeros(thresh.shape, dtype="uint8")
  cv2.drawContours(mask, [c], -1, 255, -1)

  # apply the mask to the thresholded image, then
  # count the number of non-zero pixels in the
  # bubble area
  mask = cv2.bitwise_and(thresh, thresh, mask=mask)
  total = cv2.countNonZero(mask)

  # if the current total has a larger number of total
  # non-zero pixels, then we are examining the currently
  # bubbled-in answer
  if bubbled is None or total > bubbled[0]:
   bubbled = (total, j)

 # initialize the contour color and the index of the
 # *correct* answer
 color = (0, 0, 255)
 k = ANSWER_KEY[q]

 # check to see if the bubbled answer is correct
 if k == bubbled[1]:
  color = (0, 255, 0)
  correct += 1

 # draw the outline of the correct answer on the test
 cv2.drawContours(paper, [cnts[k]], -1, color, 3)

# grab the test taker
score = (correct / 5.0) * 100
print("[INFO] score: {:.2f}%".format(score))
cv2.putText(paper, "{:.2f}%".format(score), (10, 30),
 cv2.FONT_HERSHEY_SIMPLEX, 0.9, (0, 0, 255), 2)
cv2.imshow("Original", image)
cv2.imshow("Exam", paper)
cv2.waitKey(0)

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136

# grab the test taker

score = (correct / 5.0) * 100

print("[INFO] score: {:.2f}%".format(score))

cv2.putText(paper, "{:.2f}%".format(score), (10, 30),

cv2.FONT_HERSHEY_SIMPLEX, 0.9, (0, 0, 255), 2)

cv2.imshow("Original", image)

cv2.imshow("Exam", paper)

cv2.waitKey(0)

Below you can see the output of our fully graded example image:

Figure 10: Finishing our OMR system for grading human-taken exams.

In this case, the reader obtained an 80% on the exam. The only question they missed was #4 where they incorrectly marked “C” as the correct answer (“D” was the correct choice).

Why not use circle detection?

After going through this tutorial, you might be wondering:
“Hey Adrian, an answer bubble is a circle. So why did you extract contours instead of applying Hough circles to find the circles in the image?”
Great question.
To start, tuning the parameters to Hough circles on an image-to-image basis can be a real pain. But that’s only a minor reason.
The real reason is:
User error.
How many times, whether purposely or not, have you filled in outside the lines on your bubble sheet? I’m not expert, but I’d have to guess that at least 1 in every 20 marks a test taker fills in is “slightly” outside the lines.
And guess what?
Hough circles don’t handle deformations in their outlines very well — your circle detection would totally fail in that case.
Because of this, I instead recommend using contours and contour properties to help you filter the bubbles and answers. The cv2.findContours function doesn’t care if the bubble is “round”, “perfectly round”, or “oh my god, what the hell is that?”.
Instead, the cv2.findContours function will return a set of blobs to you, which will be the foreground regions in your image. You can then take these regions process and filter them to find your questions (as we did in this tutorial), and go about your way.

Our bubble sheet test scanner and grader results

To see our bubble sheet test grader in action, be sure to download the source code and example images to this post using the “Downloads” section at the bottom of the tutorial.
We’ve already seen test_01.png as our example earlier in this post, so let’s try test_02.png :

$ python test_grader.py --image images/test_02.png

1	$ python test_grader.py --image images/test_02.png

Here we can see that a particularly nefarious user took our exam. They were not happy with the test, writing “#yourtestsux” across the front of it along with an anarchy inspiring “#breakthesystem”. They also marked “A” for all answers.
Perhaps it comes as no surprise that the user scored a pitiful 20% on the exam, based entirely on luck:

Figure 11: By using contour filtering, we are able to ignore the regions of the exam that would have otherwise compromised its integrity.

Let’s try another image:

$ python test_grader.py --image images/test_03.png

1	$ python test_grader.py --image images/test_03.png

This time the reader did a little better, scoring a 60%:

Figure 12: Building a bubble sheet scanner and test grader using Python and OpenCV.

In this particular example, the reader simply marked all answers along a diagonal:

$ python test_grader.py --image images/test_04.png

1	$ python test_grader.py --image images/test_04.png

Figure 13: Optical Mark Recognition for test scoring using Python and OpenCV.

Unfortunately for the test taker, this strategy didn’t pay off very well.
Let’s look at one final example:

$ python test_grader.py --image images/test_05.png

1	$ python test_grader.py --image images/test_05.png

Figure 14: Recognizing bubble sheet exams using computer vision.

This student clearly studied ahead of time, earning a perfect 100% on the exam.

Extending the OMR and test scanner

Admittedly, this past summer/early autumn has been one of the busiest periods of my life, so I needed to timebox the development of the OMR and test scanner software into a single, shortened afternoon last Friday.
While I was able to get the barebones of a working bubble sheet test scanner implemented, there are certainly a few areas that need improvement. The most obvious area for improvement is the logic to handle non-filled in bubbles.
In the current implementation, we (naively) assume that a reader has filled in one and only one bubble per question row.
However, since we determine if a particular bubble is “filled in” simply by counting the number of thresholded pixels in a row and then sorting in descending order, this can lead to two problems:

What happens if a user does not bubble in an answer for a particular question?
What if the user is nefarious and marks multiple bubbles as “correct” in the same row?

Luckily, detecting and handling of these issues isn’t terribly challenging, we just need to insert a bit of logic.
For issue #1, if a reader chooses not to bubble in an answer for a particular row, then we can place a minimum threshold on Line 108 where we compute cv2.countNonZero :

Figure 15: Detecting if a user has marked zero bubbles on the exam.

If this value is sufficiently large, then we can mark the bubble as “filled in”. Conversely, if total is too small, then we can skip that particular bubble. If at the end of the row there are no bubbles with sufficiently large threshold counts, we can mark the question as “skipped” by the test taker.
A similar set of steps can be applied to issue #2, where a user marks multiple bubbles as correct for a single question:

Figure 16: Detecting if a user has marked multiple bubbles for a given question.

Again, all we need to do is apply our thresholding and count step, this time keeping track if there are multiple bubbles that have a total that exceeds some pre-defined value. If so, we can invalidate the question and mark the question as incorrect.

Summary

In this blog post, I demonstrated how to build a bubble sheet scanner and test grader using computer vision and image processing techniques.
Specifically, we implemented Optical Mark Recognition (OMR) methods that facilitated our ability of capturing human-marked documents and automatically analyzing the results.
Finally, I provided a Python and OpenCV implementation that you can use for building your own bubble sheet test grading systems.
If you have any questions, please feel free to leave a comment in the comments section!
But before you, be sure to enter your email address in the form below to be notified when future tutorials are published on the PyImageSearch blog!

Mesin Belajar

Tuesday, October 4, 2016

Bubble sheet multiple choice scanner and test grader